어떻게 구별합니까? y = (secx ^ 3) sqrt (sin2x)?

대답:

# dy / dx = secx ^ 3 ((cos2x) / sqrt (sin2x) + 3x ^ 2tanx ^ 3sqrt (sin2x)) #

설명:

우리는 가지고있다. # y = uv # 어디에 #유# 과 #V# 둘 다의 기능이다. #엑스#.

# dy / dx = uv '+ vu'#

# u = secx ^ 3 #

# u '= 3x ^ 2secx ^ 3tanx ^ 3 #

# v = (sin2x) ^ (1/2) #

2 × 2cos2x = (cos2x) / sqrt (sin2x) # 2 = (sin2x) / 2 * d / dx sin2x = (sin2x)

# dy / dx = (secx ^ 3cos2x) / sqrt (sin2x) + 3x ^ 2secx ^ 3tanx ^ 3sqrt (sin2x) #

# dy / dx = secx ^ 3 ((cos2x) / sqrt (sin2x) + 3x ^ 2tanx ^ 3sqrt (sin2x)) #

체인 규칙을 사용하여 f (x) = sqrt (cote ^ (4x))를 어떻게 구별합니까?

2 차 컬러 (백색) (f '(4x)) (2x) (xx)) = sqrt (cot (ex (4x))) / sqrt (ee (4x)) f (x) = 1 / 2 * (g (x)) ^ (- 1/2) * g '(x) 색상 (흰색 ) (g (x)) = (g '(x)) ^ 2 (x) = cot (e ^ (4x)) (x)) = h (x) = e (4x) 색 (흰색) (h (x) (x) = 4xj '(x) = 4h'(x) = e ' (4x) f (x) = (-4e ^ (4x) csc ^ 2 (e ^ (4x)) (2x) (4x)) (2x4)) / 2 색 (백색) (f' (x)) = - / sqrt (cot (e ^ (4x))

당신은 어떻게 단순화합니까 (1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) div sqrt (a + 1) / ( (a-1) sqrt (a + 1) - (a + 1) sqrt (a-1)

(1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) / (a-1) sqrt (a + 1) - (a + 1) sqrt (a + 1) 1) + sqrt (a + 1)) / (sqrt (a-1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a- 1) cdot sqrt (a + 1) -sqrt (a + 1) cdot sqrt (a + 1) sqrt (a-1))) = color ( (a + 1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a + 1) (a + 1) -sqrt (a + 1))) = 컬러 (적색) (a + 1) - (sqrt (a + 1) cdot sqrt (a-1) (a + 1) = sqrt (a + 1) cdot sqrt (a-1) (sqrt (a-1) -sqrt (a + 1) (a + 1) -sqrt (a + 1))) xx ((a + 1) + sqrt (a + 1) (a + 1)) / 색 (적색) (((1 + 1))) (a-1)) / (sqrt (a-1))) xx ((sqrt (a + 1) cdot sqrt (a-1) (a + 1) cdot sqrt (a-1)) xx s

체인 규칙을 사용하여 f (x) = sqrt (ln (1 / sqrt (xe ^ x))를 어떻게 구별합니까?

그냥 규칙을 반복해서 반복하십시오. f (x) = sqrt (xe ^ x) / (xe ^ x) (1 / sqrt (xe ^ x)))) '= = 1 / (2sqrt (1 / sqrt (xe ^ x))) (ln (1 / sqrt (xe ^ x)))))) *) (ln (1 / sqrt (xe ^ x)))) == 1 / (2sqrt * sqrt (xe ^ x)) = 1 / (2 / sqrt (xe ^ x))) (1 / sqrt (1 / sqrt (xe ^ x)) '= = sqrt (xe ^ x) / (2sqrt (ln (1 / sqrt (xe ^ x) (xe ^ x) = (xe ^ x) / (2sqrt (ln (1 / sqrt (xe ^ x)))) (xe ^ x) = - sqrt (xe ^ x) / (4sqrt (1 / 2) ln (1 / sqrt (xe ^ x))))) ((xe ^ x) ^ - (3/2)) (xe ^ x) '= = sqrt 1 / sqrt ((xe ^ x) ^ 3) (xe ^ x) '= = sqrt (xe ^ x) / (4sqrt (ln (1 / sqrt (xe ^ x))) (xe ^ x) ^ 3)) (xe ^ x) == 1 / 4sqrt ((xe ^ x) / (ln (1