대답:
아래 참조
설명:
# 3sec ^ 2thetaatan ^ 2theta + 1 = sec ^ 6theta-tan ^ 6theta #
오른쪽# = sec ^ 6theta-tan ^ 6theta #
# = (sec ^ 2theta) ^ 3- (tan ^ 2theta) ^ 3 #-> 2 개의 입방체 공식의 차이를 사용하십시오
# = (sec ^ 2theta-tan ^ 2theta) (sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) #
# = 1 * (sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) #
# = sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta #
# = sec ^ 2theta sec ^ 2 세타 + sec ^ 2thetatan ^ 2theta + tan ^ 2theta tan ^ 2 세타 #
# = sec ^ 2theta (tan ^ 2theta + 1) + sec ^ 2thetatan ^ 2theta + tan ^ 2theta (sec ^ 2theta-1) #
# = sec ^ 2thetatan ^ 2theta + sec ^ 2theta + sec ^ 2thetatan ^ 2theta + sec ^ 2thetatan ^ 2theta-tan ^ 2theta #
# = sec ^ 2thetatan ^ 2theta + sec ^ 2thetatan ^ 2theta + sec ^ 2thetatan ^ 2theta + sec ^ 2theta-tan ^ 2theta #
# = 3sec ^ 2thetatan ^ 2theta + 1 #
#=# 왼쪽