대답:
#v (pi / 2) = - sqrt2 #
설명:
#if p = f (t); #
# v = d / (dt) f (t) #
# v = d / (dt) (sin (2t-pi / 4) +2) #
#v (t) = 2 * cos (2t-pi / 4) #
# "for:"t = pi / 2 #
# 2 (π / 2) = 2 * cos (2 * π / 2-π / 4) #
#v (pi / 2) = 2 * cos (pi-pi / 4) #
#v (pi / 2) = 2 * cos ((3π) / 4) #
# cos ((3π) / 4) = - cos (pi / 4) = - sqrt2 / 2 #
#v (pi / 2) = - 2 * sqrt2 / 2 #
#v (pi / 2) = - sqrt2 #