X = -pi / 3 일 때 f (x) = cscx + tanx-cotx의 법선에 대한 방정식은 무엇입니까?

대답:

#y = - (3x) /14-2.53#

설명:

# "접선": d / dx f (x) = f '(x) #

(d / dx cscx + tanx-cotx) = - 1 / (d / dx cscx + d / dx tanx d / dx cotx) = - 1 / (- cscxcotx + sec ^ 2x + csc ^ 2x) #

(-pi / 3) + csc ^ 2 (- p / 3) = -1 / (cpi (3) π / 3)) = -1 / (14/3) = - 3 / 14 #

# y = mx + c #

#f (a) = ma + c #

#csc (-pi / 3) + tan (-pi / 3) -cot (-pi / 3) = - pi / 3 (-3/14) + c #

# c = csc (-pi / 3) + tan (-pi / 3) -cot (-pi / 3) + pi / 3 (-3/14) #

# c = -2.53 #

#y = - (3x) /14-2.53#