어떻게 (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5)를 단순화합니까?

어떻게 (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5)를 단순화합니까?
Anonim

대답:

# (3x + 2) / (3x + 1) #

설명:

요소를 고려해보십시오.

# (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) /

# ((3x + 2) (x + 4)) / ((2x-1) (x + 4)) * ((2x-1))) #

factorisation에서 발견 된 동일한 용어를 취소하십시오.

# ((3x + 2) (x + 4)) / ((2x-1) (x + 4)) * ((2x-1))) = #

# (3x + 2) / (3x + 1) #