Sqrt ((x + 1) / (2x-1))를 어떻게 구별합니까?

대답:

# (3 (x + 1)) / (2 (2x-1) ^ 2 sqrt ((x + 1) / (2x-1)) #

설명:

#f (x) = u ^ n #

#f '(x) = n xx (du) / dx xxu ^ (n-1) #

이 경우:# sqrt ((x + 1) / (2x-1)) = ((x + 1) / (2x-1)) ^ (1/2)

#n = 1 / 2, u = (x + 1) / (2x-1) #

1 / 2xx (1x (2x-1) - 2xx (x + 1)) / (2x-1) 2-1) #

# = 1 / 2xx (-3) / ((2x-1) ^ 2xx ((x + 1) / (2x-1)) ^ (1 / 2-1) #

# (1) / (2 + 1) ^ 2 ((x + 1) / (2x-1)) ^ (1/2) #